FREE — INTERVIEW QUESTIONS

Analog VLSI interview questions, with worked answers and solved numericals

90+ free analog and mixed-signal questions on the MOSFET and gm/ID, single-stage amplifiers, current mirrors, differential pairs, feedback and stability, op-amps, noise, references and regulators, data converters, PLLs, mismatch and layout. Includes 18 worked answers, 8 solved numericals, Miller compensation explained pole by pole and a gm, ro and gain calculator.

550+ Analog VLSI Interview Questions ebook cover
ANALOG VLSI EBOOK · 580 QUESTIONS · 27 CHAPTERS

Get the complete analog question bank, fully answered

580 questions with interview-ready answers and tips, 25 solved numericals, 20 SPICE circuit exercises and 30 debugging scenarios.

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Analog interviews are conversations at a whiteboard. The interviewer draws a circuit and asks for its gain, its output resistance, its poles, its noise, and what you would change to meet a specification. There are fewer candidates than for digital roles, but the bar is high: you're expected to reason, estimate and explain trade-offs, not recite.

Strong answers draw the small-signal picture first, give a quick hand estimate with its approximation stated, and finish with what it means for the design. Start with the equations and the calculator, skim the 50 questions by topic, then try each worked answer and numerical before you open it. Device background is on the CMOS and semiconductor devices pages.

HOW IT'S ASKED

Three levels of an analog interview

LEVEL 1

Hand analysis

Small-signal models, the four basic stages, mirrors and the differential pair. Expect “what's the gain?”, “what's the output resistance?” and quick numericals.

LEVEL 2

Design trade-offs

Op-amps, compensation, noise, references and regulators: how you'd size a block to a specification and what you'd give up for speed, gain, noise or power.

LEVEL 3

Silicon and sign-off

Mismatch, layout, parasitics, PVT corners, Monte Carlo and debugging: “it passed every corner, so why does silicon ring?”

HOW TO ANSWER

Six habits of strong analog answers

01

Draw it first

Sketch the small-signal picture and name which impedance each node sees before writing any formula.

02

Estimate, then refine

Give the quick answer with its approximation stated (“assuming ro >> RD”), then add the correction if asked.

03

Name the trade-off

Every analog answer gives something up: gain for headroom, noise for power, speed for matching. Say which.

04

Watch units and 2π

Hertz versus radians per second, and milli- versus micro-, cause most wrong numericals. Do a sanity check before you finish.

05

Think in corners

Say which corner is worst for the specification you're discussing: slow/hot for speed, fast/cold for stability, and mismatch for offset.

06

Remember the layout

Mention matching, parasitics and coupling where they matter. It shows you've seen a block go to silicon.

KEY EQUATIONS

The analog relations interviewers expect you to know cold

Simple square-law and small-signal forms, good for hand estimates. Real designs check them against simulation and gm/ID lookup tables.

TRANSCONDUCTANCEgm = 2ID/Vov = √(2μCox(W/L)ID)Square law, strong inversion. In weak inversion gm = ID/(nUT).
OUTPUT RESISTANCEro ≈ 1/(λID) = VA/IDLonger L raises VA and ro.
INTRINSIC GAINgmro = 2VA/VovIndependent of current in strong inversion.
COMMON SOURCEAv = −gm(ro ∥ Rload)With degeneration: Gm = gm/(1 + gmRS).
CASCODERout ≈ gm2ro2ro1Costs about one Vov of headroom per device.
SINGLE-STAGE OTAGBW = gm/(2πCL) · SR = Itail/CLTwo-stage Miller: GBW = gm1/(2πCC), SR = Itail/CC.
FEEDBACKACL = A/(1 + Aβ) ≈ 1/βLoop gain Aβ sets accuracy, bandwidth extension and stability.
PHASE MARGINtarget ≈ 60° · two-pole loop: p2 ≥ 2.2 × GBW45° rings noticeably; 90° is a single pole.
NOISEresistor 4kTR · MOSFET 4kTγ/gm (input-referred) · sampled kT/C√(kT/C) ≈ 64 µV rms on 1 pF at 300 K.
DATA CONVERTERSSNRideal = 6.02N + 1.76 dB · ENOB = (SINAD − 1.76)/6.02Jitter: SNR = −20 log(2πfinσt).
MISMATCHσ(ΔVT) = AVT/√(WL)Quadruple the area to halve the offset.
TRY IT

gm, ro and gain calculator

Square-law estimate for one transistor in saturation, plus what it means for a single-stage OTA driving CL.

gm–
ro–
INTRINSIC GAIN–
gm/ID–
OTA GBW = gm/2πCL–
kT/C NOISE ON CL–

 

STAGES COMPARED

The basic amplifier stages side by side

“Which stage would you use here, and why?” comes up in almost every analog round. Learn each one's gain, impedances and catch.

STAGEVOLTAGE GAININPUT RESISTANCEOUTPUT RESISTANCETYPICAL USETHE CATCH
Common source−gmRout (high)Very high (gate)ro ∥ Rload (high)Main gain stageMiller multiplies Cgd
CS with degeneration−Rload/(1/gm + RS)Very highRaised by (1 + gmRS)Linear, predictable gainGain and headroom traded for linearity
Source follower< 1, about gm/(gm + gmb)Very high≈ 1/gm (low)Buffer, level shiftBody effect and lost swing
Common gate+gmRout≈ 1/gm (low)HighCurrent input, wideband, cascodeLow input impedance loads the source
Cascode−gm1(gm2ro2ro1 ∥ Rload)Very high≈ gmro2 (very high)High-gain single stageHeadroom and swing
Differential pairgmRout (differential)Very highAs the loadInput stage, rejects common modeNeeds a tail and, if fully differential, CMFB
BROWSE BY TOPIC

50 analog VLSI interview questions across 10 topics

A sample of what analog interviewers ask most. The 580-question ebook goes much deeper on each topic and answers every question.

MOSFET & gm/ID

How analog designers see one transistor.

  • Why do analog designers think in overdrive voltage rather than in VGS?
  • Why does gm rise linearly with current in weak inversion but only as a square root in strong inversion?
  • You double W at constant current. What happens to gm, Vov and the device capacitances?
  • Why is fT lower for a device biased at high gm/ID?
  • How does body effect show up in a stage whose source is not at ground?

Single-Stage Amplifiers

The four stages every circuit is built from.

  • Why does swapping a resistor load for a current-source load raise a common-source stage's gain so much?
  • Why does adding a source resistor make a common-source stage more linear?
  • Where would you use a common-gate stage instead of a common-source one?
  • Why is a source follower's output resistance about 1/gm, and when is that useful?
  • A diode-connected load gives very predictable gain. Why is the gain so low?

Current Mirrors & Biasing

Copying currents accurately across a chip.

  • Why is the reference device of a mirror diode-connected?
  • Why do mirror devices usually use a longer channel and a larger overdrive than the input pair?
  • How do you scale a mirror's output by 4:1 so that the ratio survives process variation?
  • What is a constant-gm bias circuit, and why does it need a start-up path?
  • Why are bias references usually sent across a chip as currents rather than voltages?

Differential Pairs

The input stage of almost every amplifier.

  • Why is a differential pair insensitive to a common-mode input, and what breaks that in practice?
  • An NMOS-input pair stops working when its input common-mode level drops close to ground. Why?
  • Why does a pair with an active current-mirror load give a single-ended output with full differential gain?
  • What happens to the pair's gm and linear range if you halve the tail current at fixed device size?
  • Why would you choose a PMOS input pair over an NMOS one?

Frequency Response & Stability

Poles, zeros and why amplifiers ring.

  • Why does the Miller effect make Cgd look so large at the input of a high-gain stage?
  • How do you estimate the dominant pole of a circuit quickly, without solving the full transfer function?
  • Why is an amplifier in unity-gain feedback the hardest configuration to stabilise?
  • What's the difference between open-loop gain, loop gain and closed-loop gain?
  • How do you simulate loop gain without disturbing the DC operating point?

Op-Amps & Fully Differential Circuits

Turning stages into a usable amplifier.

  • When would you choose a folded-cascode OTA over a telescopic one?
  • Why does a two-stage op-amp usually swing closer to the rails than a single-stage cascode?
  • Why is a telescopic cascode awkward to use as a unity-gain buffer?
  • Name two ways to sense the output common-mode level, and the drawback of each.
  • Why can a two-stage op-amp slew more slowly than its compensation capacitor alone suggests?

Noise

Where the floor of every analog spec comes from.

  • Why is the input-referred noise of an amplifier set mostly by its first stage?
  • Why do flicker noise and offset favour large-area input devices?
  • How does a chopper amplifier remove 1/f noise, and what does it leave behind?
  • Why is 1/f noise a serious problem for a sensor amplifier but rarely for an RF amplifier?
  • Why does a larger sampling capacitor reduce noise but cost power?

References & Regulators

Clean, stable voltages for everything else.

  • Why does adding a PTAT voltage to VBE give a reference near 1.2 V?
  • Why does a CMOS bandgap use bipolar transistors at all?
  • Why is a PMOS pass device preferred in a low-dropout regulator?
  • Why does an LDO's stability depend on its load current?
  • Why can ripple at a few megahertz pass through a regulator that rejects 50 Hz hum well?

Data Converters & Switched Capacitors

Where analog meets digital.

  • Why does a switched-capacitor circuit need non-overlapping clock phases?
  • Why does the order in which the switches of a capacitor sampler open matter?
  • Compare SAR, pipeline and sigma-delta ADCs by speed, resolution and power.
  • What do DNL and INL tell you about a converter's transfer curve?
  • Why does a segmented DAC use thermometer coding for its MSBs?

PLLs, Mismatch & Layout

The parts that make silicon match simulation.

  • Why is a small extra capacitor placed across the series RC of a PLL loop filter?
  • How does layout deal differently with random mismatch and with gradients across the die?
  • Why are dummy fingers placed at both ends of a matched array?
  • Why should a sensitive analog node never run parallel to a clock line, and how do you shield it?
  • What does a guard ring around an analog block protect against?

These are samples. The full bank is six times larger.

580 questions in 27 chapters, all answered: 25 solved numericals, 20 SPICE exercises, 30 debugging scenarios, plus an annotated sign-off report and a 40-question rapid-fire round.

See the full question bank
N1 · COMMON-GATE INPUTBEGINNERA common-gate stage has gm = 2 mS, ro = 50 kΩ and a load RD = 20 kΩ. Find its input resistance. What if the load is an ideal current source?Show solution ↓
Rin = (ro + RD) / (1 + gm·ro)
    = (50k + 20k) / (1 + 2m × 50k)
    = 70k / 101  ≈  693 Ω

With RD → ∞ (ideal current-source load):
Rin → very large

Note: the textbook “1/gm” (500 Ω here) only holds when RD is small compared with ro. With a high-impedance load, a common-gate stage stops looking like a low-impedance input.

N2 · DIFFERENTIAL PAIRBEGINNERAn NMOS pair has a 200 µA tail, Vov = 0.2 V per device and resistive loads of 10 kΩ. Find the differential gain and the input that fully steers the tail.Show solution ↓
ID = 100 µA per side
gm = 2·ID / Vov = 2 × 100 µA / 0.2 V = 1 mS
Adm = gm·RD = 1 mS × 10 kΩ = 10  (20 dB)

Full steering at |Vid| = √2 · Vov ≈ 0.28 V

Note: the pair is only reasonably linear well inside that limit. Raising Vov widens the linear range but lowers gm for the same current.

N3 · CMRR FROM LOAD MISMATCHINTERMEDIATESame pair, tail output resistance RSS = 100 kΩ, and the two loads differ by 1%. Estimate the CMRR.Show solution ↓
ΔRD = 1% × 10 kΩ = 100 Ω
Acm→dm ≈ ΔRD / (1/gm + 2·RSS)
         = 100 / (1k + 200k) ≈ 5.0 × 10^-4
Adm = 10
CMRR = 10 / 5.0e-4 ≈ 20,000  ≈ 86 dB

Note: CMRR is set by mismatch and tail impedance together. A cascoded tail raises RSS; at high frequency the tail's capacitance lowers it, so CMRR falls with frequency.

N4 · FULL-POWER BANDWIDTHBEGINNERAn op-amp's slew rate is 10 V/µs. What is the highest frequency at which it can output an undistorted 1 V-peak sine wave?Show solution ↓
Max slope of Vp·sin(2πft) = 2πf·Vp
Set 2πf·Vp = SR
f = SR / (2π·Vp) = 10 V/µs / (2π × 1 V)
  ≈ 1.6 MHz

Note: above this the output turns into a triangle wave no matter what the small-signal bandwidth says. Large-signal and small-signal limits are separate specifications.

N5 · NOISE BANDWIDTHINTERMEDIATEA 1 kΩ resistor's noise passes through a single-pole filter with f3dB = 1 MHz. Find the RMS noise at 300 K.Show solution ↓
Noise density = √(4kTR) = √(4 × 1.38e-23 × 300 × 1000)
              ≈ 4.07 nV/√Hz
ENBW (single pole) = (π/2)·f3dB ≈ 1.57 MHz
Vrms = 4.07 nV × √(1.57e6) ≈ 5.1 µV

Note: integrating to f3dB alone underestimates the noise by about 20%. A single-pole roll-off lets noise through well past the corner.

N6 · SEGMENTED DACINTERMEDIATEA 10-bit current DAC uses 4 thermometer-coded MSBs and 6 binary LSBs. How many current elements does it need, and how many switch at the mid-scale step 511 → 512?Show solution ↓
MSBs: 2^4 − 1 = 15 unit elements, each worth 64 LSB
LSBs: 6 binary-weighted elements (1, 2, 4 ... 32)
Total: 21 elements (versus 1023 fully thermometer)

511 = 7×64 + 63  ->  512 = 8×64 + 0
1 MSB element turns on, 6 LSB elements turn off: 7 switch
(A fully binary DAC switches all 10 bits here)

Note: fewer elements switching at major transitions means smaller glitches and better DNL, which is why the MSBs are thermometer-coded.

N7 · SC INTEGRATORINTERMEDIATEA switched-capacitor integrator has Cs = 1 pF, Cf = 4 pF and a 1 MHz clock. Find its per-cycle gain and its unity-gain frequency.Show solution ↓
Per cycle: Vout[n] = Vout[n−1] + (Cs/Cf)·Vin
           Cs/Cf = 0.25

For f << fs:  ωu ≈ (Cs/Cf)·fs
fu = 0.25 × 1 MHz / 2π ≈ 40 kHz

Note: the integrator's time constant is set by a capacitor ratio and the clock, both accurate on chip, rather than by an absolute RC product that can vary by ±20%.

N8 · REFERENCE TEMPCOBEGINNERA 1.2 V reference stays between 1.198 V and 1.202 V from −40 °C to 125 °C. What is its temperature coefficient by the box method?Show solution ↓
TC = (Vmax − Vmin) / (Vnom × ΔT)
   = 4 mV / (1.2 V × 165 °C)
   ≈ 20 ppm/°C

Note: the box method describes the worst case across the range, not the slope at room temperature. A curved bandgap can have zero slope at 27 °C and still score 20 ppm/°C.

80 dB 0 dB log f → p1p2 p1′p2′ p1 moves down p2 moves up GBW uncompensated: crosses 0 dB at −40 dB/dec compensated: −20 dB/dec
UncompensatedWith CCPole movement
  1. Find the high-impedance nodes. A two-stage op-amp has two: the first-stage output and the second-stage output. Each gives a pole, and without compensation the two sit close together.
  2. See the problem. With two nearby poles the gain is already falling at 40 dB per decade when it crosses 0 dB, so the phase margin is close to zero and the closed loop rings or oscillates.
  3. Add CC across the second stage. Miller multiplication makes it look like CC(1 + A2) at the first-stage output, so the first pole drops to a much lower frequency: p1′ ≈ 1/(R1gm2R2CC).
  4. The second pole moves up. At high frequency CC connects the second stage's gate to its drain, so it behaves like a diode-connected device and the output pole rises to about gm2/CL.
  5. Set the numbers. GBW = gm1/CC. For about 60° of phase margin, put p2′ at roughly 2.2 × GBW or higher, and keep the right-half-plane zero at gm2/CC well above GBW, or remove it with a nulling resistor.
  6. Verify. Run a loop-gain (stability) simulation at every corner and load, and a closed-loop step to confirm the overshoot matches the margin you expect.
Why not just make the load capacitor larger instead?

For a two-stage op-amp, a larger CL lowers the second pole (gm2/CL), which reduces phase margin. That's the opposite of a single-stage OTA, where the output node is dominant and a larger CL makes it more stable.

What does compensation do to the slew rate?

During a large step the first stage delivers its full tail current into CC, so the internal slew rate is about Itail/CC. A larger CC buys phase margin and costs both GBW and slew rate unless the current goes up too. The output stage must also be able to charge CL that fast.

Why is the right-half-plane zero a problem?

It raises the gain like a normal zero but adds phase lag like a pole, the worst of both. It comes from CC feeding the signal forward around the second stage. A series resistor near 1/gm2, or a buffer in the compensation path, removes it.

How is phase margin measured in simulation?

Break the loop without disturbing the DC operating point, for example with a stability analysis that injects a test signal (Middlebrook or Tian's method), and read the phase of the loop gain where its magnitude crosses 0 dB. The Analog VLSI ebook covers compensation, verification and the sign-off report in depth.

Corner frequency of an RC low-pass with 1 kΩ and 159 pF?

About 1 MHz.

A voltage gain of 1000 in dB?

60 dB.

A voltage ratio of 0.5 in dB?

About −6 dB.

Phase contributed by one pole at its own frequency?

−45°.

Phase of a single pole a decade above its frequency?

About −84°.

Effect of a left-half-plane zero on phase?

It adds phase lead.

Which stage has the lowest output resistance?

The source follower, about 1/gm.

Which stage avoids Miller multiplication at its input?

The common-gate stage.

Slope of a magnitude plot above two poles?

−40 dB per decade.

What is PSRR?

How much supply ripple is rejected relative to the signal gain, in dB.

Clock requirement for switched-capacitor phases?

Two non-overlapping phases.

DNL of −1 LSB means?

A missing code.

INL in one line?

Deviation of the transfer curve from a straight line.

What does a chopper amplifier remove?

Offset and 1/f noise, by modulating them out of the signal band.

Why add dummy fingers?

So every active finger sees the same surroundings.

Global versus local variation?

Global shifts all devices together (corners); local makes neighbours differ (mismatch).

Unit of input-referred noise density?

V/√Hz.

What is headroom?

The voltage left across a device to keep it in saturation.

A large output step settles in which two phases?

Slewing first, then linear (small-signal) settling.

What does a guard ring do?

Collects stray substrate carriers: isolation and latch-up protection.

COMMON MISTAKES

What costs candidates the most in analog rounds

×

Ignoring headroom

A design with perfect gain on paper fails if the stacked devices don't all stay in saturation at the lowest supply and the extreme input common-mode. Count Vovs before quoting gain.

×

Quoting the typical corner only

Interviewers expect you to say what happens at slow/hot and fast/cold, and with Monte Carlo mismatch. Margins exist for the corners, not for typical.

×

Forgetting the load

GBW, phase margin and slew rate all depend on the load capacitance. An answer without CL is incomplete.

×

Numbers without units or 2π

Mixing hertz and radians per second, or millisiemens and siemens, is the most common way to get a numerical wrong by a factor of 6 or 1000.

×

Skipping the small-signal picture

Jumping to formulas without naming which device sees which impedance leads to wrong answers on unfamiliar circuits. Draw it first, then calculate.

×

Treating layout as someone else's job

Matching, parasitics and coupling decide whether an analog block works. Designers are expected to specify and review layout, not just hand over a schematic.

QUICK FAQ

Before you start preparing

Which topics should a fresher prepare first?

The MOSFET in saturation and its small-signal model, the common-source stage with different loads, current mirrors, the differential pair, frequency response and the Miller effect, feedback and phase margin, and basic op-amp structures. Then noise, references and data converters.

Do analog roles require an M.Tech?

Many analog teams prefer an M.Tech or MS because the work builds on deep circuit coursework and a thesis project, but strong B.Tech candidates with a solid project, simulation experience and good hand analysis do get hired, especially into layout and characterisation roles first.

Which simulator should I practise on?

Any SPICE you can run regularly. LTspice and ngspice are free, and Xschem with ngspice works with open PDKs such as SKY130 if you want real transistor models. What matters is checking your hand calculations against simulation.

How much mathematics is expected?

Mostly algebra and simple complex-frequency reasoning: small-signal models, poles and zeros, decibels and logarithms, and noise integration. Interviewers want quick estimates with stated approximations more than long derivations.

Will analog design be automated the way digital design was?

Parts of it are being automated: sizing optimisers, layout generators and AI-assisted tools are improving quickly. But specifications, architecture choices, trade-offs and silicon debug still depend on engineers who understand circuits, so the skills interviewers test remain in demand.

How is this different from the CMOS round?

The CMOS round covers devices, digital gates, power, SRAM and reliability. The analog round assumes that background (see the CMOS questions) and asks you to analyse and design circuits that process continuous signals: gain, bandwidth, stability, noise and matching.

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